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\[
\begin{aligned}
\lim\limits_{x\to+\infty}\frac{a\sqrt{2x^2+3}+2017}{2x+2018} &= \lim\limits_{x\to+\infty}\frac{a\sqrt{x^2(2 + \frac{3}{x^2})}+2017}{2x+2018} \\
&= \lim\limits_{x\to+\infty}\frac{ax(\sqrt{2+\frac{3}{x^2}}+\frac{2017}{x})}{x(2+\frac{2018}{x})} \\
&= \frac{a\sqrt{2}}{2}
\end{aligned}
\]
$\lim\limits_{x\to+\infty}\frac{a\sqrt{2x^2+3}+2017}{2x+2018} = \frac{1}{2} \implies \frac{a\sqrt{2}}{2} = \frac{1}{2} \implies a = \frac{\sqrt{2}}{2}$