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miscs/misc.tex
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miscs/misc.tex
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\[
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\begin{aligned}
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\lim\limits_{x\to+\infty}\frac{a\sqrt{2x^2+3}+2017}{2x+2018} &= \lim\limits_{x\to+\infty}\frac{a\sqrt{x^2(2 + \frac{3}{x^2})}+2017}{2x+2018} \\
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&= \lim\limits_{x\to+\infty}\frac{ax(\sqrt{2+\frac{3}{x^2}}+\frac{2017}{x})}{x(2+\frac{2018}{x})} \\
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&= \frac{a\sqrt{2}}{2}
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\end{aligned}
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\]
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Mà $\lim\limits_{x\to+\infty}\frac{a\sqrt{2x^2+3}+2017}{2x+2018} = \frac{1}{2} \implies \frac{a\sqrt{2}}{2} = \frac{1}{2} \implies a = \frac{\sqrt{2}}{2}$
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